Mathematics - Sequence & Series Question with Solution | TestHub

If a is the first term and d is the common difference of the associated A.P. $\frac{1}{\mathrm{q}}=\frac{1}{\mathrm{a}}+(2\mathrm{p}-1)\mathrm{d},\frac{1}{\mathrm{p}}=\frac{1}{\mathrm{a}}+(2\mathrm{q}-1)\mathrm{d}$ $\Rightarrow \mathrm{d}=\frac{1}{2\mathrm{pq}}$ If h is the $2(\mathrm{p}+\mathrm{q}{)}^{\mathrm{th}}$ term $\frac{1}{\mathrm{h}}=\frac{1}{\mathrm{a}}+(2\mathrm{p}+2\mathrm{q}-1)\mathrm{d}$ $=\frac{1}{\mathrm{q}}+\frac{1}{\mathrm{p}}=\frac{\mathrm{p}+\mathrm{q}}{\mathrm{pq}}$