The sum of the series : ( 2 ) 2 + 2 ( 4 ) 2 + 3 ( 6 ) 2 + … upto 10 terms is :

2 2 + 2 ( 4 ) 2 + 3 ( 6 ) 2 + …… upto 10 terms = 2 2 [ 1 3 + 2 3 + 3 3 + …… upto 10 terms ] = 4 ⋅ ( 2 10 × 11 ) 2 = 12100

Mathematics - Sequence & Series Question with Solution | TestHub

MathematicsSequence & SeriesSpecial sequences/seriesHard2 minPYQ_2013

MathematicsHardstatement

The sum of the series : $(2)^{2} + 2 (4)^{2} + 3 (6)^{2} + \dots$ upto 10 terms is :

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Answer:

Solution:

$2^{2} + 2 (4)^{2} + 3 (6)^{2} + \dots\dots$ upto 10 terms $= 2^{2} [1^{3} + 2^{3} + 3^{3} + \dots\dots$ upto 10 terms $]$ $= 4 \cdot (\frac{10 \times 11}{2})^{2} = 12100$

Stream:JEESubject:MathematicsTopic:Sequence & SeriesSubtopic:Special sequences/series

⏱ 2mℹ️ Source: PYQ_2013

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