Mathematics - Quadratic Equation Question with Solution | TestHub

MathematicsQuadratic EquationLocation of rootsMedium2 minQB

MathematicsMediumsingle choice

For $x^{2} - (α + 2) ∣ x ∣ + 9 = 0$ to have real solutions, the range of ' $α$ ' is

Answer:

Solution:

$α = \frac{x ^{2} + 9}{∣ x ∣} - 2 = ∣ x ∣ + \frac{9}{∣ x ∣} - 2$ $α \geq 4$ .

$α \geq 4$

Stream:JEESubject:MathematicsTopic:Quadratic EquationSubtopic:Location of roots

⏱ 2mℹ️ Source: QB

Loading discussions...