The remainder when 2 + [ 1 ! + 2 ( 2 !) + 3 ( 3 !) + …… + 10 ( 10 !)] is divided by 11 ! is

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MathematicsQuadratic EquationMiscellaneous/MixedMedium2 minQB

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The remainder when $2 + [1! + 2 (2!) + 3 (3!) + \dots\dots + 10 (10!)]$ is divided by $11!$ is

Answer:

Solution:

$n (n!) = (n + 1)! - n!$

and proceed

Stream:JEESubject:MathematicsTopic:Quadratic EquationSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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