(L-1)If x 2 + 5 = 2 x − 4 cos ( a + b x ) where a , b ∈ ( 0 , 5 ) , is satisfied for at least one real x , then the maximum value of ( a + ( B ) is

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x 2 − 2 x + 5 = − 4 cos ( a + b x ) ​ − 4 cos ( a + b x ) ≥ 4 → cos ( a + b x ) ≤ − 1 ​ ​ ​ ∴ cos ( a + b ) = − 1 ∴ a + b = π or 3 π

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