Mathematics - Quadratic Equation Question with Solution | TestHub

${\mathrm{Lime}}_{x\to \infty }{\mathrm{e}}^{-x}|\mathrm{P}(x)|=0$

and ${\mathrm{Lt}}_{x\to -\infty }{\mathrm{e}}^{-x}|\mathrm{P}(x)|=\infty$

consequently there is an $x_0\in \mathrm{R}$ such that ${\mathrm{e}}^{-x_0}\left|\mathrm{P}\left(x_0\right)\right|=1$