The sum of squares of all integral values of a > − 5 for which the inequality x 2 − ax + 6 a 0 , f ( 1 ) < 0 , f ( − 1 ) < 0 value of a are − 4 , − 3 , − 2 , − 1 ( − 4 ) 2 + ( − 3 ) 2 + ( − 2 ) 2 + ( − 1 ) 2 = 30

Mathematics - Quadratic Equation Question with Solution | TestHub

MathematicsQuadratic EquationMiscellaneous/MixedMedium2 minQB

MathematicsMediuminteger

The sum of squares of all integral values of $a > - 5$ for which the inequality $x^{2} - ax + 6 a < 0$ is satisfied for all $x \in (- 1, 1)$ must be equal to 6 k then k is

$D > 0, f (1) < 0, f (- 1) < 0$

value of a are $- 4, - 3, - 2, - 1$

$(- 4)^{2} + (- 3)^{2} + (- 2)^{2} + (- 1)^{2} = 30$

Answer:

Solution:

$f (x) = x^{2} - a x + 6 a$

Stream:JEESubject:MathematicsTopic:Quadratic EquationSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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