Mathematics - Quadratic Equation Question with Solution | TestHub

MathematicsQuadratic EquationTheory of equationsHard2 minQB

MathematicsHardsingle choice

Let $f (x) = x^{2} + 5 x + 6$ , then the number of real roots of $(f (x))^{2} + 5 f (x) + 6 - x = 0$ is

Answer:

Solution:

This given eq. is equivalent to $f (f (x)) - x = 0$ .

Since $f (x) = x$ has no real roots, $f (f (x)) = x$ also has no real roots.

Therefore, the number of real roots is 0.

Stream:JEESubject:MathematicsTopic:Quadratic EquationSubtopic:Theory of equations

⏱ 2mℹ️ Source: QB

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