Mathematics - Quadratic Equation Question with Solution | TestHub

MathematicsQuadratic EquationInequationMedium2 minQB

MathematicsMediuminteger

(L-3)Find the least integral value of a such that $9 - a^{2} + 2 a x - x^{2} > 16 - x^{2}$ for at least one positive x .

Answer:

Solution:

$y = 9 - a^{2} + 2 a x - x^{2}$

$(x - a)^{2} + y^{2} = 9$

For given inequality to hold for positive x .

$a - 3 < 4 \Rightarrow a < 7 \Rightarrow a = 6$

Stream:JEESubject:MathematicsTopic:Quadratic EquationSubtopic:Inequation

⏱ 2mℹ️ Source: QB

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