Mathematics - Quadratic Equation Question with Solution | TestHub

$\begin{array}{rl}& \text{ (I) }x<2\\ & -x^2+2x-3x+9+1=0\\ & \Rightarrow x^2+x-10=0\\ & \Rightarrow x=\frac{-1+\sqrt{41}}{2},\frac{-1-\sqrt{41}}{2}\\ & \times \sqrt{}\end{array}$
$\begin{array}{rl}& \text{ (II) }2\le x<3\\ & \Rightarrow x^2-2x-3x+9+1=0\\ & \Rightarrow x^2-5x+10=0\\ & \text{ D }<0\\ & \text{ (III) }x\ge 3\\ & x^2-2x+3x-9+2=0\\ & \Rightarrow x^2+x-8=0\\ & x=\frac{-1+\sqrt{32}}{2},\frac{-1-\sqrt{32}}{2}\\ & \times \times \end{array}$
1 real roots