Mathematics - Quadratic Equation Question with Solution | TestHub

$|x+1||x+3|-4|x+2|+5=0$ case-1 $\begin{array}{rl}& x\le -3\\ & (x+1)(x+3)+4(x+2)+5=0\\ & x^2+4x+3+4x+8+5=0\\ & x^2+8x+16=0\\ & (x+4{)}^2=0\\ & x=-4\end{array}$ case-2 $\begin{array}{rl}& -3\le x\le -2\\ & -x^2-4x-3+4x+8+5=0\\ & -x^2+10=0\\ & x=\pm \sqrt{10}\end{array}$ case-3 $\begin{array}{rl}& -2\le x\le -1\\ & -x^2-4x-3-4x-8+5=0\\ & -x^2-8x-6=0\\ & x^2+8x+6=0\\ & x=\frac{-8\pm 2\sqrt{10}}{2}=-4\pm \sqrt{10}\end{array}$ case-4 $\begin{array}{rl}& x\ge -1\\ & x^2+4x+3-4x-8+5=0\\ & x^2=0\\ & x=0\end{array}$
No. of solution $=2$