Mathematics - Quadratic Equation Question with Solution | TestHub

$\because x^2=|x{|}^2$ 

$9{\left|x\right|}^2-18\left|x\right|+5=0$

$\Rightarrow (3\left|x\right|-1)(3\left|x\right|-5)=0$

$\Rightarrow \left|x\right|=\frac{1}{3},\frac{5}{3}$

$\therefore x=\frac{1}{3},\frac{-1}{3},\frac{5}{3},\frac{-5}{3}$

product of roots $=\frac{1}{3}\left(-\frac{1}{3}\right)\left(\frac{5}{3}\right)\left(\frac{-5}{3}\right)=\frac{25}{81}$