Mathematics - Quadratic Equation Question with Solution | TestHub

Dividing $\mathrm{R}$ at $\frac{2}{3},\frac{4}{3}$ and $2,$ analyse 4 cases. When $\mathrm{x}\le \frac{2}{3},$ the inequality becomes $2-3x+4-3x+6-3x\ge 12$ implying $-9x\ge 0\Rightarrow x\le 0$ when $\mathrm{x}\ge 2$ the ineqality becomes $3x-2+3x-4+3x-6\ge 12$ Implying $9\mathrm{x}\ge 24\Rightarrow \mathrm{x}\ge 8/3$ The inequality in invalid in the other two sections. $\therefore$ either $x\le 0$ or $x\ge 8/3$