Mathematics - Quadratic Equation Question with Solution | TestHub

The second equation can be rewritten as $a{\left(\frac{x}{x+1}\right)}^2+b\left(\frac{x}{x+1}\right)+c=0$ and hence its roots correspond to $\frac{\mathrm{x}}{\mathrm{x}+1}=\alpha$ and $\frac{x}{x+1}=\beta$. Hence $x=\frac{\alpha }{1-\alpha }$ and $\frac{\beta }{1-\beta }$.