1 0 n + 3 ( 4 n + 2 ) + 5 is divisible by ( n ∈ N )

1 0 n + 3 ( 4 n + 2 ) + 5 Taking n = 2 , 1 0 2 + 3 × 4 4 + 5 = 100 + 768 + 5 = 873 Therefore this is divisible by 9.

Mathematics - Quadratic Equation Question with Solution | TestHub

MathematicsQuadratic EquationCommon RootsMedium2 minPYQ_2009

MathematicsMediumsingle choice

$1 0^{n} + 3 (4^{n + 2}) + 5$ is divisible by $(n \in N)$

Answer:

Solution:

$1 0^{n} + 3 (4^{n + 2}) + 5 Taking n = 2, 1 0^{2} + 3 \times 4^{4} + 5 = 100 + 768 + 5 = 873$ Therefore this is divisible by 9.

Stream:BITSATSubject:MathematicsTopic:Quadratic EquationSubtopic:Common Roots

⏱ 2mℹ️ Source: PYQ_2009

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