In a triangle ABC , if a = 2 , B = 6 0 ∘ and C = 7 5 ∘ , then b equals

A = 18 0 ∘ − 6 0 ∘ − 7 5 ∘ = 18 0 ∘ − 13 5 ∘ = 4 5 ∘ Now, s i n A a = s i n B b ⇒ s i n 4 5 ∘ 2 = s i n 6 0 ∘ b ⇒ b = 1/ 2 2 ⋅ ( 3 /2 ) = 6

Mathematics - Properties of Triangles Question with Solution | TestHub

MathematicsProperties of TrianglesGeneralMedium2 minPYQ_2012

MathematicsMediumsingle choice

In a triangle $ABC,$ if $a = 2, B = 6 0^{\circ}$ and $C = 7 5^{\circ}$ , then b equals

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$A = 18 0^{\circ} - 6 0^{\circ} - 7 5^{\circ} = 18 0^{\circ} - 13 5^{\circ} = 4 5^{\circ}$ Now, $\frac{a}{s i n A} = \frac{b}{s i n B}$ $\Rightarrow \frac{2}{s i n 4 5 ^{\circ}} = \frac{b}{s i n 6 0 ^{\circ}} \Rightarrow b = \frac{2 \cdot ( 3 /2 )}{1/ 2} = 6$

Stream:BITSATSubject:MathematicsTopic:Properties of TrianglesSubtopic:General

⏱ 2mℹ️ Source: PYQ_2012

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