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Mathematics - Properties of Triangle Question with Solution | TestHub

MathematicsProperties of TriangleGeneral (basic formula based)Medium2 minQB

MathematicsMediumsingle choice

In triangle ABC, $a^{2}$ + $c^{2}$ = $2002 b^{2}$ . Find (cot A+cot C)/cot B.

Options:

Answer:

Solution:

Cot addition and sine law yield (cot A+cot C)/cot B = $sin^{2}$ B/[sin A sin C cos B] = $2 b^{2}$ /[ $a^{2}$ + $c^{2}$ - $b^{2}$ ] = 2/(2002-1)=2/2001.

Stream:JEESubject:MathematicsTopic:Properties of TriangleSubtopic:General (basic formula based)

⏱ 2mℹ️ Source: QB

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