Mathematics - Properties of Triangle Question with Solution | TestHub

MathematicsProperties of Triangler1,r–R formula basedMedium2 minQB

MathematicsMediumsingle choice

If b+c=3a in triangle ABC, find cot(B/2)cot(C/2).

Answer:

Solution:

cot(B/2)cot(C/2)=[s(s-b)/ $Δ$ ][s(s-c)/ $Δ$ ]=s/(s-a), using $Δ^{2}$ =s(s-a)(s-b)(s-c). Since 2s=a+b+c=4a, s=2a and s-a=a, so the product is 2.

Stream:JEESubject:MathematicsTopic:Properties of TriangleSubtopic:r1,r–R formula based

⏱ 2mℹ️ Source: QB

Loading discussions...