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Mathematics - Properties of Triangle Question with Solution | TestHub

MathematicsProperties of Triangler1,r–R formula basedMedium2 minQB

MathematicsMediumsingle choice

If the exradii r_1:r_2:r_3 are 1:2:3, find a:b:c.

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Answer:

Solution:

Let exradii be k,2k,3k. Since 1/r=1/r_1+1/r_2+1/r_3, 1/r=11/(6k). Also s= $Δ$ /r and s-a= $Δ$ /r_1 etc. Thus a/ $Δ$ =1/r-1/r_1=5/(6k), b/ $Δ$ =1/r-1/r_2=4/(3k), c/ $Δ$ =1/r-1/r_3=3/(2k). Hence 5:8:9.

Stream:JEESubject:MathematicsTopic:Properties of TriangleSubtopic:r1,r–R formula based

⏱ 2mℹ️ Source: QB

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