Mathematics - Properties of Triangle Question with Solution | TestHub
MathematicsProperties of TriangleGeneral (basic formula based)Medium2 minQB
MathematicsMediumsingle choice
In triangle ABC, cos A+sin A-2/(cos B+sin B)=0. Find (a+b)/c.
Options:
Answer:
A
Solution:
(cos A+sin A)(cos B+sin B)=2. The product is cos(A-B)+sin(A+B), each summand at most 1, hence A=B and A+B=90°. Thus A=B=45°, C=90°, and (a+b)/c=.
Stream:JEESubject:MathematicsTopic:Properties of TriangleSubtopic:General (basic formula based)
⏱ 2mℹ️ Source: QB
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