In a △ A BC , a = 5 , b = 4 and tan 2 C = 9 7 , then measure of side ' c ' is

cos C = 1 + 9 7 1 − 9 7 = 8 1 ∴ c 2 = 25 + 16 − 2 ⋅ 5 ⋅ 4 ⋅ 8 1 = 36

Mathematics - Properties of Triangle Question with Solution | TestHub

MathematicsProperties of TriangleGeneral (basic formula based)Easy2 minQB

MathematicsEasyinteger

In a $△ A BC, a = 5, b = 4$ and $tan \frac{C}{2} = \frac{7}{9}$ , then measure of side ' c ' is

Answer:

Solution:

$cos C = \frac{1 - \frac{7}{9}}{1 + \frac{7}{9}} = \frac{1}{8}$

$∴ c^{2} = 25 + 16 - 2 \cdot 5 \cdot 4 \cdot \frac{1}{8} = 36$

Stream:JEESubject:MathematicsTopic:Properties of TriangleSubtopic:General (basic formula based)

⏱ 2mℹ️ Source: QB

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