In △ ABC if ∠ C = 9 0 ∘ , then the value of r + R a + b is

∠ c = 9 0 0 ⇒ 2 ( r + R ) = a + b ⇒ r + R a + b = 2 x`

Mathematics - Properties of Triangle Question with Solution | TestHub

MathematicsProperties of Triangler1,r–R formula basedEasy2 minQB

MathematicsEasyinteger

In $△ ABC$ if $∠ C = 9 0^{\circ}$ , then the value of $\frac{a + b}{r + R}$ is

Answer:

Solution:

$∠ c = 9 0^{0} \Rightarrow 2 (r + R) = a + b \Rightarrow \frac{a + b}{r + R} = 2$ x`

Stream:JEESubject:MathematicsTopic:Properties of TriangleSubtopic:r1,r–R formula based

⏱ 2mℹ️ Source: QB

Loading discussions...