In a triangle A BC , if side b = 8 , side c = 10 and angle A = 3 0 ∘ , then the area of the triangle is:

The area of a triangle given two sides and the included angle is Area = 2 1 b c sin A . Substituting the given values, Area = 2 1 ( 8 ) ( 10 ) sin 3 0 ∘ = 2 1 ( 80 ) ( 2 1 ) = 40 ( 2 1 ) = 20 square units.

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Mathematics - Properties of Triangle Question with Solution | TestHub

MathematicsProperties of TriangleMiscellaneous/Mixed (Include Hight & Distance)Easy2 minai-gemini

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In a triangle $A BC$ , if side $b = 8$ , side $c = 10$ and angle $A = 3 0^{\circ}$ , then the area of the triangle is:

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Answer:

Solution:

The area of a triangle given two sides and the included angle is Area $= \frac{1}{2} b c sin A$ . Substituting the given values, Area $= \frac{1}{2} (8) (10) sin 3 0^{\circ} = \frac{1}{2} (80) (\frac{1}{2}) = 40 (\frac{1}{2}) = 20$ square units.

Stream:JEESubject:MathematicsTopic:Properties of TriangleSubtopic:Miscellaneous/Mixed (Include Hight & Distance)

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