Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityConditional probabilityMedium2 minQB

MathematicsMediumsingle choice

A binomial distribution has mean 4 and variance 4/3. Find the probability of at least two successes.

Answer:

Solution:

$n p = 4, n pq = 4/3$ , so $q = 1/3, p = 2/3, n = 6$ . Thus $P (X \geq 2) = 1 - q^{6} - 6 p q^{5} = 716/729$ .

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:Conditional probability

⏱ 2mℹ️ Source: QB

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