Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityGeneral (Event SS, Definitions, Odd against/Favour)Easy2 minQB

MathematicsEasyinteger

In a group of people, if 4 are selected at a random, the probability that the any two of the four do not have same month of birth is $p$ then $\frac{96 p}{11}$ is equal to

Answer:

Solution:

Required probability $= \frac{^{12} C _{4} ⌊ 4}{1 2 ^{4}} = \frac{55}{96}$

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:General (Event SS, Definitions, Odd against/Favour)

⏱ 2mℹ️ Source: QB

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