Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityGeneral (Event SS, Definitions, Odd against/Favour)Medium2 minQB

MathematicsMediuminteger

Two numbers are selected at random from set of the first 100 natural numbers. The probability that the product obtained is divisible by 3 is k then $\frac{150 k}{83}$ is equal to

Answer:

Solution:

Required probability $= \frac{^{33} C _{2} + ^{33} C _{1} ^{67} C _{1}}{^{100} C _{2}}$

$= \frac{83}{150}$

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:General (Event SS, Definitions, Odd against/Favour)

⏱ 2mℹ️ Source: QB

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