Four players play a round-robin tournament, with independent fair outcomes and no ties. If the probability of neither an undefeated nor a winless player is a/b in lowest terms, find |2a-b|.
Answer:
2.00
Solution:
Inclusion-exclusion gives probability 3/8. Hence |2a-b|=|6-8|=2.

Question

Four players play a round-robin tournament, with independent fair outcomes and no ties. If the probability of neither an undefeated nor a winless player is a/b in lowest terms, find |2a-b|.

TestHub · Accepted Answer

Inclusion-exclusion gives probability 3/8. Hence |2a-b|=|6-8|=2.

Mathematics - Probability Question with Solution | TestHub

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