Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityGeneral (Event SS, Definitions, Odd against/Favour)Hard2 minQB

MathematicsHardinteger

3 couples have to be seated around a circle. Let p be the probability that no couple is together then the value of 30 p is

Answer:

Solution:

$p = \frac{5 ! - ^{3} C _{1} ( 4 !) \cdot ( 2 !) + ^{3} C _{2} ( 3 !) \cdot ( 2 !) \cdot ( 2 !) - ^{3} C _{3} ( 2 !) \cdot ( 2 !) \cdot ( 2 !) \cdot ( 2 !)}{5 !} = \frac{120 - 144 + 72 - 16}{120} = \frac{4}{15}$ So $30 p = 8$

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:General (Event SS, Definitions, Odd against/Favour)

⏱ 2mℹ️ Source: QB

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