Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityTotal probability/Bay's TheoremMedium2 minQB

MathematicsMediumsingle choice

Passage / Comprehension

Urns I, II, III contain (W,B)=(3,3), (2,3), (4,2), respectively. A die is rolled: a prime number selects Urn I, a composite number selects Urn II, and otherwise Urn III is selected. A white ball is drawn.

Find the posterior probability that Urn III was selected.

Options:

Answer:

Solution:

Bayes gives $\frac{( 1/6 ) ( 4/6 )}{( 3/6 ) ( 3/6 ) + ( 2/6 ) ( 2/5 ) + ( 1/6 ) ( 4/6 )} = 20/89$ .

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:Total probability/Bay's Theorem

⏱ 2mℹ️ Source: QB

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