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MathematicsProbabilityMiscellaneous/MixedMedium2 minQB

MathematicsMediuminteger

There are four balls of different colors and four boxes of colors, same as those of the balls. The number of ways in which the balls, one each in a box, could be placed such that a ball does not go to a box of its own color, is

Answer:

Solution:

∴ Number of ways of putting all the 4 balls into boxes of different colour.

$= 4 I [1 - \frac{1}{1 !} + \frac{1}{2 !} - \frac{1}{3 !} + \frac{1}{4 !}] = 4 I (\frac{1}{2} - \frac{1}{6} + \frac{1}{24}) = 2.4 (\frac{12 - 4 - 1}{24}) = 9$

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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