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Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityGeneral (Event SS, Definitions, Odd against/Favour)Medium2 minQB

MathematicsMediumsingle choice

From a bag containing 10 distinct balls, 6 balls are drawn simultaneously and replaced. Then 4 balls are drawn. The probability that exactly 3 balls are common to the drawings is

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Answer:

Solution:

Let S be the sample space of the composite experiment of drawing 6 in the first draw and then four in second draw then $n (S) =^{10} C_{6} \times^{10} C_{4}$

∴ Required Probability $= \frac{^{10} C _{6} \times ^{6} C _{3} \times ^{4} C _{1}}{^{10} C _{6} \times ^{10} C _{4}} = \frac{80 \times 24}{10 \times 9 \times 8 \times 7} = \frac{8}{21}$

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:General (Event SS, Definitions, Odd against/Favour)

⏱ 2mℹ️ Source: QB

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