Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityGeneral (Event SS, Definitions, Odd against/Favour)Easy2 minQB

MathematicsEasysingle choice

A die is rolled three times, the probability of getting large number than the previous number is

Answer:

Solution:

If the $2^{n d}$ number is $i (i > 1)$ , the number of favorable ways is $(i - 1) \times (6 - i)$ .

The total number of favorable ways, $n (E)$ , is:

$n (E) = i = 1 \sum 6 (i - 1) \times (6 - i) = 1 \times 4 + 2 \times 3 + 3 \times 2 + 4 \times 1 = 20$

The required probability is:

$\frac{20}{216} = \frac{5}{54}$

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:General (Event SS, Definitions, Odd against/Favour)

⏱ 2mℹ️ Source: QB

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