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Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityGeneral (Event SS, Definitions, Odd against/Favour)Medium2 minQB

MathematicsMediumsingle choice

Out of 10 persons sitting at a round table. Three persons are selected at random one after the other. The chance that no two of the selected are together.

Options:

Answer:

Solution:

Out of 10 persons 3 can be selected in $^{10}_{P_{3}}$ ways $= 10.9.8 = 720$ . First person in 10 ways. Other 2 in $7 C_{2}$ ways in which 2 are together in 6 ways.

Hence $P (E) = \frac{10 \times ( 7 _{C_{2}} - 6 ) \times 2}{720} = \frac{5}{12} .$

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:General (Event SS, Definitions, Odd against/Favour)

⏱ 2mℹ️ Source: QB

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