Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityGeneral (Event SS, Definitions, Odd against/Favour)Easy2 minPYQ_2024

MathematicsEasysingle choice

The probability of getting 10 in a single throw of three fair dice is

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Answer:

Solution:

Total outcomes $= 216$ Now, number of cases of getting 10 from 3 dices in single throw are Case $1 : 1 + 3 + 6 \to$ outcomes $= 3! = 6$ Case $2 : 1 + 4 + 5 \to$ outcomes $= 3$ ! $= 6$ Case $3 : 2 + 2 + 6 \to$ outcomes $= \frac{3 !}{2 !} = 3$ Case $4 : 2 + 3 + 5 \to$ outcomes $= 3! = 6$ Case $5 : 2 + 4 + 4 \to$ outcomes $= \frac{3 !}{2 !} = 3$ Case $6 : 3 + 3 + 4 \to$ outcomes $= \frac{3 !}{2 !} = 3$ Favourable outcomes $= 27$ $∴$ Probability $= \frac{27}{216} = \frac{1}{8}$ $\Rightarrow \Rightarrow (x + 24) (x - 20) x = 0 = 20$

Stream:BITSATSubject:MathematicsTopic:ProbabilitySubtopic:General (Event SS, Definitions, Odd against/Favour)

⏱ 2mℹ️ Source: PYQ_2024

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