Mathematics - Probability Question with Solution | TestHub

For a distribution of random variable $x$, $\alpha =P\left(X^6<3\right)=P\left(X^6=1\right)+P\left(X^6=2\right)$ $\begin{array}{rl}& =\lambda +2\lambda =3\lambda \\ & \text{ and }\beta =P\left(X^6<2\right)=P\left(X^6=3\right)+P\left(X^6=4\right)\\ & =3\lambda +4\lambda =3\lambda \\ & \therefore \alpha :\beta =3:7\end{array}$