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MathematicsProbabilityTotal probability/Bay's TheoremMedium2 minPYQ_2021
MathematicsMediumsingle choice

In a group of400people,160are smokers and non-vegetarian;100are smokers and vegetarian and the remaining140are non-smokers and vegetarian. Their chances of getting a particular chest disorder are35%,20%and10%respectively. A person is chosen from the group at random and is found to be suffering from the chest disorder. The probability that the selected person is a smoker and non-vegetarian is :

Options:

Answer:
D
Solution:

Consider following events
A : Person chosen is a smoker and non
vegetarian.

B : Person chosen is a smoker and vegetarian.

C : Person chosen is a non-smoker and vegetarian

E : Person chosen has a chest disorder

Given

PA=160400PB=100400PC=140400

PEA=35100PEB=20100PEC=10100

To find

PAE=PAPEAPA·PEA+PB·PEB+PC·PEC

=160400×35100160400×35100+100400×20100+140400×10100

=2845

option 4

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:Total probability/Bay's Theorem
2mℹ️ Source: PYQ_2021

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