Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityRandom Variable and its Probability DistributionEasy2 minPYQ_2021

MathematicsEasysingle choice

The mean and variance of a random variable $X$ having binomial distribution are 4 and 2 respectively, then $P (X = 1)$ is

Options:

Answer:

Solution:

$n p n pq \Rightarrow q P (X = 4 = 2 = \frac{1}{2}, p = \frac{1}{2}, n = 8 = 1) =^{8} C_{1} (\frac{1}{2}) (\frac{1}{2})^{7} = 8 \cdot \frac{1}{2 ^{8}} = \frac{1}{2 ^{5}} = \frac{1}{32}$

Stream:BITSATSubject:MathematicsTopic:ProbabilitySubtopic:Random Variable and its Probability Distribution

⏱ 2mℹ️ Source: PYQ_2021

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