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MathematicsProbabilityRandom Variable and its Probability DistributionMedium2 minPYQ_2015

MathematicsMediumsingle choice

If the mean and the variance of a binomial variate $X$ are $2 & 1$ respectively, then the probability that $X$ takes a value greater than or equal to one is:

Options:

Answer:

Solution:

$n p = 2$

$n p q = 1$

$∴ q = \frac{1}{2}$

$p = 1 - q = \frac{1}{2}$

$n = 4$

$P (X \geq 1) = {1 -}^{4} C_{0} {(\frac{1}{2})}^{4} {(\frac{1}{2})}^{0}$

$1 - \frac{1}{16} = \frac{15}{16}$

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:Random Variable and its Probability Distribution

⏱ 2mℹ️ Source: PYQ_2015

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