A boy is throwing stones at a target. The probability of hitting the target at any trial is 2 1 The probability of hitting the target 5 th time at the 10 th throw is:

Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityGeneral (Event SS, Definitions, Odd against/Favour)Hard2 minPYQ_2012

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A boy is throwing stones at a target. The probability of hitting the target at any trial is $\frac{1}{2}$ The probability of hitting the target 5 th time at the 10 th throw is:

Options:

Answer:

Solution:

The probability of hitting the target 5 th time at the 10 th throw $= P ($ the probability of hitting the target 4 times in the first 9 throws) $P ($ the probability of hitting the target at the 10 th throw $) =$ $[^{9} C_{4} (\frac{1}{2})^{4} (\frac{1}{2})^{5}] (\frac{1}{2}) = \frac{9 !}{4 ! 5 !} \times (\frac{1}{2})^{10} = \frac{63}{2 ^{9}}$

Stream:BITSATSubject:MathematicsTopic:ProbabilitySubtopic:General (Event SS, Definitions, Odd against/Favour)

⏱ 2mℹ️ Source: PYQ_2012

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