If A and B are mutually exclusive events and if P ( B ) = 3 1 , P ( A ∪ B ) = 21 13 , then P ( A ) is equal to

For mutually exclusive events P ( A ∪ B ) = P ( A ) + P ( B ) ⇒ P ( A ) = 7 2

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MathematicsProbabilityAddition theoremEasy2 minPYQ_2011

MathematicsEasysingle choice

If $A$ and $B$ are mutually exclusive events and if $P (B) = \frac{1}{3}, P (A \cup B) = \frac{13}{21}$ , then $P (A)$ is equal to

Answer:

Solution:

For mutually exclusive events $P (A \cup B) = P (A) + P (B) \Rightarrow P (A) = \frac{2}{7}$

Stream:BITSATSubject:MathematicsTopic:ProbabilitySubtopic:Addition theorem

⏱ 2mℹ️ Source: PYQ_2011

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