At a telephone enquiry system the number of phone cells regarding relevant enquiry follow Poisson distribution with an average of 5 phone calls during 10-minute time intervals. The probability that th

Question

At a telephone enquiry system the number of phone cells regarding relevant enquiry follow Poisson distribution with an average of 5 phone calls during 10-minute time intervals. The probability that there is at the most one phone call during a 10-minute time period is

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Answer:

D

Solution:

$P (X = r) = \frac{e ^{- m} m ^{r}}{r !}$ $P (X \leq 1) = P (X = 0) + P (X = 1)$ $= e^{- 5} + 5 \times e^{- 5} = \frac{6}{e ^{5}}$

TestHub · Accepted Answer

P ( X = r ) = r ! e − m m r ​ P ( X ≤ 1 ) = P ( X = 0 ) + P ( X = 1 ) = e − 5 + 5 × e − 5 = e 5 6 ​

Mathematics - Probability Question with Solution | TestHub

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