The equations of two sides AB and AC of a triangle ABC are 4 x + y = 14 and 3 x − 2 y = 5 , respectively. The point ( 2 , − 3 4 ) divides the third side BC internally in the ratio 2 : 1 . the equati

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The equations of two sides AB and AC of a triangle ABC are 4 x + y = 14 and 3 x − 2 y = 5 , respectively. The point ( 2 , − 3 4 ​ ) divides the third side BC internally in the ratio 2 : 1 . the equation of the side BC is

TestHub · Accepted Answer

​ 3 2 x 2 ​ + x 1 ​ ​ = 2 , 3 2 ( 2 3 x 2 ​ − 5 ​ ) + ( 14 − 4 x 1 ​ ) ​ = 3 − 4 ​ 2 x 2 ​ + x 1 ​ = 6 , 3 x 2 ​ − 4 x 1 ​ = − 13 x 2 ​ = 1 , x 1 ​ = 4 ​ So, C ( 1 , − 1 ) , B ( 4 , − 2 ) m = 3 − 1 ​ Equation of BC : y + 1 = 3 − 1 ​ ( x − 1 ) ​ 3 y + 3 = − x + 1 x + 3 y + 2 = 0 ​

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