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MathematicsPointLocusMedium2 minPYQ_2018
MathematicsMediumsingle choice

The locus of the point of intersection of the lines2x-y+42k=0and2kx+ky-42=0(kis any non-zero real parameter) is

Options:

Answer:
C
Solution:

Given equation of lines are2x-y+42k=0     ...1

and 2kx+ky-42=0      ...2 

Eliminating k from 1 and 2,

2x+y2x-y-42=42

2x2-y2=-32

y232-x216=1, which is a hyperbola.

e=1+1632=32 and length of transverse axis

=82.

Stream:JEESubject:MathematicsTopic:PointSubtopic:Locus
2mℹ️ Source: PYQ_2018

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