Mathematics - Point Question with Solution | TestHub

MathematicsPointGeneral (Distance + section formula)Easy2 minPYQ_2016
MathematicsEasysingle choice

A straight line through originOmeets the lines3y=10-4x and8x+6y+5=0at pointsAandBrespectively. Then,Odivides the segmentABin the ratio

Options:

Answer:
C
Solution:

Let Ar1cosθ, r1sinθ

A Lies on straight line 4x+3y=10

4r1cosθ+3r1sinθ=10

r14cosθ+3sinθ=10
r1=104cosθ+3sinθ

Let B-r2cosθ, -r2sinθ

B lies on line 8x+6y+5=0

8-r2cosθ+6-r2sinθ+5=0

r28cosθ+6sinθ-5=0r2=58cosθ+6sinθ
r1r2=41

Stream:JEESubject:MathematicsTopic:PointSubtopic:General (Distance + section formula)
2mℹ️ Source: PYQ_2016

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