Mathematics - Point Question with Solution | TestHub

$P(2,2); Q(6,-1); R(7,3)$

$S$is the midpoint of$Q$and$R$.

$\therefore S\equiv \left(\frac{13}{2}, 1\right)$

$\therefore$Slope of$PS=\frac{2-1}{2-\frac{13}{2}}=\frac{1}{\left(\frac{-9}{2}\right)}=\frac{-2}{9}$

Therefore, the equation of the line passing through$(1,-1)$and parallel to$PS$is

$y+1=\frac{-2}{9}\left(x-1\right)$

$\therefore 9y+9=-2x+2$

$\therefore 2x+9y+7=0$