(A) Required number of selection = 2 n C 0 + 2 n C 1 + … + 2 n C n = 2 2 n − 1 + 2 1 ( n ! ) 2 ( 2 n )!

Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationMiscellaneous/MixedMedium2 minQB

MathematicsMediumsingle choice

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Answer:

Solution:

(A) Required number of selection $=^{2 n} C_{0} +^{2 n} C_{1} + \dots +^{2 n} C_{n} = 2^{2 n - 1} + \frac{1}{2} \frac{( 2 n )!}{( n ! ) ^{2}}$

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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