Mathematics - Permutation & Combination Question with Solution | TestHub
Match the counts. Column I: (A) Twelve balls each of red, black and white, identical by color, are given to two children, 18 each. (B) Split five boys and five girls into two teams of five, both mixed-gender. (C) Assign six distinct book bundles one per distinct box, when two boxes are too small for three of the bundles. (D) Choose two balls from five colors with six uniquely numbered balls per color, of the same color or the same number. Column II: (p) 125 (q) 127 (r) 135 (s) 144
Column I | Column II |
|---|---|
(A) Twelve balls each of red, black and white, identical by color, are given to two children, 18 each. | (p) 125 |
(B) Split five boys and five girls into two teams of five, both mixed-gender. | (q) 127 |
(C) Assign six distinct book bundles one per distinct box, when two boxes are too small for three of the bundles. | (r) 135 |
(D) Choose two balls from five colors with six uniquely numbered balls per color, of the same color or the same number. | (s) 144 |
Options:
Answer:
Solution:
A: bounded triples summing to 18 yield . B: the teams are unlabeled, giving . C: for two restricted boxes choose ordered distinct bundles from the other three (3‧2), then arrange the rest (4!), giving 144. D: .
