Let N be the number of ordered triplets ( x , y , z ) ∈ N 3 satisfying x yz = 910 . Which statements are correct?

Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationDistributionMedium2 minQB

MathematicsMediummultiple choice

Let $N$ be the number of ordered triplets $(x, y, z) \in N^{3}$ satisfying $x yz = 910$ . Which statements are correct?

Answer:

C, D

Solution:

$910 = 2 \cdot 5 \cdot 7 \cdot 13$ . Each prime factor can be assigned independently to one of $x, y, z$ , so $N = 3^{4} = 81 = 9^{2} = 3^{4}$ .

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:Distribution

⏱ 2mℹ️ Source: QB

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