Let x 1 , x 2 , … . , x k are the total divisors of positive integer n. If ∑ i = 1 k x i = 93 and ∑ i = 1 k x i 1 = 50 93 then the value of k is

( ∑ x i ) / ( ∑ x i 1 ) = n

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Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationFundamental PrincipleMedium2 minQB

MathematicsMediumsingle choice

Let $x_{1}, x_{2}, \dots ., x_{k}$ are the total divisors of positive integer n. If $\sum_{i = 1}^{k} x_{i} = 93$ and $\sum_{i = 1}^{k} \frac{1}{x _{i}} = \frac{93}{50}$ then the value of $k$ is

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Answer:

Solution:

$(\sum x_{i}) / (\sum \frac{1}{x _{i}}) = n$

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:Fundamental Principle

⏱ 2mℹ️ Source: QB

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