Mathematics - Permutation & Combination Question with Solution | TestHub
Match the counts. Column I: (A) Positive unequal integral solutions to (B) Trailing zeros of 100! (C) Triangles from vertices of a regular 72-gon with the same number of polygon vertices between each consecutive pair of triangle vertices (D) Arrangements of SUNDAY beginning neither in S nor ending in Y Column II: (p) 504 (q) 36 (r) 24 (s) 552
Column I | Column II |
|---|---|
(A) Positive unequal integral solutions to | (p) 504 |
(B) Trailing zeros of 100! | (q) 36 |
(C) Triangles from vertices of a regular 72-gon with the same number of polygon vertices between each consecutive pair of triangle vertices | (r) 24 |
(D) Arrangements of SUNDAY beginning neither in S nor ending in Y | (s) 552 |
Options:
Answer:
Solution:
A: 4! times the count of with sum 20 gives 552 . B: 100 has two trailing zeros, while 100 ! has . C: equal circular gaps require equilateral triples, one for each rotation modulo three, giving . D: .
Note: entry B refers to 100! (24 trailing zeros); the printed stem said the number 100.
